This diagram describes the fetch-execution cycle. How can i perform another step for multiplication just after the step 4 and what value will be loaded in Program counter, AC and IR?
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Hi,
In fetch execution cycle it load one instruction register and the two data registers. And the PC points the next instruction to be fetched. After that the instruction will execute at next clock cycle.
Therefore the PC value does not change after step 4. Only the IR value will change. The value should be relevant to the multiplication.
Hellow Alber Aqil,
I am giving you important outline about fetch-execution cycle.
In Operand fetch step:
1.MAR <-PC
2.MDR <-MEM[MAR]
3.IR <-MDR
4.PC <-PC+1
5.DECODER <- IR.OP
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In execution cycle:
