Does any one here know how to find the margin of error for a 95 confidence interval. I need to know as soon as possible. Thanks in advance for the help.
How Do I Find The Margin Of Error For A 95 Confidence Interval
The method for calculating the margin of error for a given sample proportion is described as under. First find the sample size, n and the sample proportion….. The multiply it . Divide the result by n. After this take the square root of the value so obtained. Multiply this result by the apt z*-value for desired confidence level.