Hi All
I need to write a program that will show the reverse order of an array’s elements.
What will be code for reversing the values of an array?
For example: if array = 5,8,12,19,25
Then program will show the out put as:
25,19,12,8,5
Any help would really be appreciated.
All you need to do is to take these 5 numbers from the user and save them in an array. Firstly you will show the array in original order means with original index. After that you will show the array in reverse order, means you will start from the last index and one by one you will decrease the index instead of increasing.
How we can reverse the index of an array??????????????????
Dear Sahil
I need more help. I am confused about the index of an array. How I will calculate the index of an array and how I will reverse?
Waiting
You will declare an array with index 5 as: num[5];
Then you will show the numbers of array as
for(i=0,i<5,i++)
cout<<num[i];
To show in reverse order you will write code as:
for(i=4,i>=0;i–)
cout<<num[i];
I don’t have C++ compiler at the moment. Try this with proper statements in compiler. If you don’t get the true result, please send me your code. So I can help you more.
#include<iostream.h>
#include<conio.h>
void main()
{
clrscr
int num[5],I;
for(i=0,i<5,i++)
{
Cout<<”enter the number”<<endl;
Cin>>num[i];
}
count<<”n the array in actual order”<<endl;
for(i=0,i<5,i++)
cout<<num[i];
count<<”n the array in reverse order”<<endl;
for(i=4,i>=0;i–)
cout<<num[i];
getch();
}
Thanks a lot Mark Jason
It really helps me out to understand fully the concept of array and arrays with indexing.
Regards
