HTTP 500 trouble to get users in DirectPush technology

Asked By 0 points N/A Posted on -

Hello experts,

I wish someone can assist me troubleshoot this. On our exchange server 2003, I have faced a constant HTTP 500 trouble to get users in DirectPush technology. Here I am giving a number of hardware background information:

Front-End server:
Exchange 2003 SP2 with Windows Server 2003

Back-End Server:
Exchange 2003 SP2 with Windows Server 2003

We tried to follow these articles:
Deleting and recreating Microsoft-Server-ActiveSync in IIS

Problems in Synchronizing a Pocket PC with Exchange Server 2003 when using SSL and Forms-Based Authentication in OWA

And ..
How did we setup our Exchange for OWA, OMA, ActiveSync and RPC over HTTPS

But we still get the problem… The accurate event ID error is the common:

Event Type:      Error
Event Source:      Server ActiveSync
Event Category:      None
Event ID:      3005
Date:            3/21/2006
Time:            10:02:53 AM
User:            XXXYYY
Computer:      FRONT-END
Unexpected Exchange mailbox Server error: Server: [XXX.XXX.XXX] User: [[email protected]] HTTP status code: [400]. Verify that the Exchange mailbox Server is working correctly.

I know this has been conversed before but it looks that all accessible options are not working.  I almost required to calling MS, but hopefully you can give the proper answers.
Need a solution to solve this. Please help. Thanks.

Answered By 55 points N/A #104888

HTTP 500 trouble to get users in DirectPush technology


You will get this error every time when there are too many users who are trying to access your server and your server is limited n resources.

  1. the other reason is that the authorization credentials that are being used are incorrect.
  • Update the IIS on your local machine and try running some sample files from Microsoft.
  • Update the exchange server to service pack 1 or 2 lately.
  • This is very important for the things to go as you planned them.
  • Once done, close all other instances and try running the one which is giving you the error.
  • After that you can just run the program and it will not give any sort of error.

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