Hi,
I recently came across a hard task to handle and I would appreciate if the experts would assist me to determine the solution. How do I determine the channel capacity for a teleprinter channel that has a 300-Hz bandwidth and a signal to noise ratio of 3 decibels?
Hello,
You can do that by this equation:
C = B log2(1 + SNR)
Our have, W = 300 Hz (SNR)dB= 3
After, SNR = 100.3
C = 300 log2 (1 + 100.3) = 300 log2(2.995) = 474 bps
Thank You.
Hi Paplov,
Channel capacity can be defined as the amount of information that can be transmitted successfully over a given communication channel without attenuation and interference by noise. To calculate the channel capacity in this particular problem, the following procedure can be followed:
Take C for channel capacity and SNR for signal-to-noise ratio
SNR in decibels(dB) = 10log3 = 1.995
Formula for channel capacity
C = B * log2(1+SNR)
C= 300 * log2(1 + 1.995) = 474.76 bit/s
Hope this will help you.
Thank you.
