 ## Groove shark error: invalid literal for Float (): iii.

Asked By 0 points N/A Posted on -

Hi all,
I was working on a linear regression program, and when I try to convert the input file data to a float, I got this error.

Groove shark error: invalid literal for float (): iii. I'm using Windows XP SP2.

Here is a picture to better describe my problem… Error:

Grooveshark error: invalid literal for float(): iii

Any idea what’s going on? SHARE
Answered By 15 points N/A #82204

## Groove shark error: invalid literal for Float (): iii.

Linear regression wildly used in the information technology environment for simple linear equation y = mx + b, while in place m is the slope and b is the intercept.

This program will be utilized for the method this is completely a program which utilized in the Programming language, which is sensitive while compiling in the windows platform.

To avoid this error please be make sure that software program has obtain the latest patches and updates.

Check with the windows OS updates.

Apart from this check with the below stings to fix if that helps!

#! /usr/bin/env python

import sys

import os

from numpy import *

numLst = [] #an empty list

if len(sys.argv) == 2:

infile = open(sys.argv, 'r')

for x in infile:

numLst.append([float(i) for i in x.strip().split()])

elif len(sys.argv) <2:

infilename = raw_input("Name of file: ")

data = open(infilename, 'r')

for x in data:

numLst.append([float(i) for i in x.strip().split()])

elif len(sys.argv) > 2:

raise SyntaxError, "Too many arguments"

a = array(numLst)

print a

b = a[0:, 1] #this is just me manipulating the list a bit

print b

c = a[0:,1]

print

bA = b[:1]

g = bA

print numLst 