Asked By
shellyylove
60 points
N/A
Posted on - 07/31/2011
Calculate the minimum time required to download, two million bytes of information, using each of the following technologies:
-
V. 32 modem
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V. 32bis modem
-
V. 90 modem
-
Cable Modem
Answered By
James20
5 points
N/A
#96350
Calculate the minimum time required
Hi,
You can find this material helpful.
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Formula to calculate time = total number of bits to be downloaded/data rate in bps = total number of bytes x8/data rate in bps.
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a. V. 32
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Here
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Total data = 2,000,000 bits
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Data rate = 9.6 kbps = 9600 bps
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Hence
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Time = (2,000,000 × 8) /9600 = 1668 s
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b. V. 32bis
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Total data = 2,000,000 bits
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Data rate = 14.4 kbps = 14400 bps
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Time = (2,000,000 × 8) / 14400= 1112 s
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c. V. 90
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Total data = 2,000,000 bits
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Data rate = 56 kbps = 56000 bps
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Time = (2,000,000 × 8) / 56000 = 286 s
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d. Cable Modem
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We can calculate time based on the assumption of 10 Mbps data rate which is usually used:
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Total data = 2,000,000 bits
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Data rate = 10 Mbps = 1000 kbps = 10,000,000 bps
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Time = (2,000,000 × 8) / 10,000,000 = 1.6 s.