Groove shark error: invalid literal for Float (): iii.

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Hi all,
I was working on a linear regression program, and when I try to convert the input file data to a float, I got this error.

Groove shark error: invalid literal for float (): iii. I'm using Windows XP SP2.

Here is a picture to better describe my problem…

Error:

Alert                                                          

Grooveshark error: invalid literal for float(): iii

Any idea what’s going on?

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Answered By 0 points N/A #82204

Groove shark error: invalid literal for Float (): iii.

qa-featured

Linear regression wildly used in the information technology environment for simple linear equation y = mx + b, while in place m is the slope and b is the intercept.

This program will be utilized for the method this is completely a program which utilized in the Programming language, which is sensitive while compiling in the windows platform.

To avoid this error please be make sure that software program has obtain the latest patches and updates.

Check with the windows OS updates.

Apart from this check with the below stings to fix if that helps!     

#! /usr/bin/env python

  import sys

  import os

  from numpy import *

  numLst = [] #an empty list

  if len(sys.argv) == 2:

      infile = open(sys.argv[1], 'r')

      for x in infile:

          numLst.append([float(i) for i in x.strip().split()])

  elif len(sys.argv) <2:

      infilename = raw_input("Name of file: ")

      data = open(infilename, 'r')

      for x in data:

          numLst.append([float(i) for i in x.strip().split()])

  elif len(sys.argv) > 2:

      raise SyntaxError, "Too many arguments"

  a = array(numLst)

  print a

  b = a[0:, 1] #this is just me manipulating the list a bit

  print b

  c = a[0:,1]

  print

  bA = b[:1]

  g = bA

  print numLst

Hope the above information will help you out.

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