Asked By
shellyylove
60 points
N/A
Posted on - 07/31/2011
Calculate the minimum time required to download, two million bytes of information, using each of the following technologies:
-
V. 32 modem
-
V. 32bis modem
-
V. 90 modem
-
Cable Modem
Answered By
James20
5 points
N/A
#96350
Calculate the minimum time required
Hi,
You can find this material helpful.
Formula to calculate time = total number of bits to be downloaded/data rate in bps = total number of bytes x8/data rate in bps.
a. V. 32
Here
Total data = 2,000,000 bits
Data rate = 9.6 kbps = 9600 bps
Hence
Time = (2,000,000 × 8) /9600 = 1668 s
b. V. 32bis
Total data = 2,000,000 bits
Data rate = 14.4 kbps = 14400 bps
Time = (2,000,000 × 8) / 14400= 1112 s
c. V. 90
Total data = 2,000,000 bits
Data rate = 56 kbps = 56000 bps
Time = (2,000,000 × 8) / 56000 = 286 s
d. Cable Modem
We can calculate time based on the assumption of 10 Mbps data rate which is usually used:
Total data = 2,000,000 bits
Data rate = 10 Mbps = 1000 kbps = 10,000,000 bps
Time = (2,000,000 × 8) / 10,000,000 = 1.6 s.