C++ operators and their precedence level

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How many operators are used in C++ language?

Also describe the precedence of operators.

Write a program to show which operator has high precedence. 

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Best Answer by Chris Phil
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Answered By 0 points N/A #124167

C++ operators and their precedence level

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I do not have the exact number of operators in C++, but some are as follows:

  1. Assignment operator (=)
  2. Arithmetic operators [(+)addition, (-)subtraction, (*)multiplication, (/)division, (%)modulo]
  3. Increase operator (++) and Decrease operator (–)
  4. Relational and Equality Operators [(==)equal to, (!=)not equal to, (>),greater than, (<)less than, (>=)greater than or equal to, (<=)less than or equal to]
  5. Logical operators [(!)not, (&&)and, (||)or]
  6. Conditional operator (?)
  7. Comma operator (,)
  8. Bitwise operators [(&)bitwise AND, (|)bitwise inclusive OR, (^)bitwise exclusive OR, (~)unary complement, (<<)shift left, (>>)shift right]

 

From most priority to lowest priority, the order is as follows:

 

Priority

Level

Operator

Description

Grouping

1

() [] . -> ++ —

postfix

Left-to-right

2

++ — ~ !

unary (prefix)

Right-to-left

* &

indirection and reference (pointers)

+ –

unary sign operator

3

(type)

type casting

Right-to-left

4

.* ->*

pointer-to-member

Left-to-right

5

* / %

multiplicative

Left-to-right

6

+ –

additive

Left-to-right

7

<< >>

shift

Left-to-right

8

< > <= >=

relational

Left-to-right

9

== !=

equality

Left-to-right

10

&

bitwise AND

Left-to-right

11

^

bitwise XOR

Left-to-right

12

|

bitwise OR

Left-to-right

13

&&

logical AND

Left-to-right

14

||

logical OR

Left-to-right

15

?:

conditional

Right-to-left

16

= *= /= %= += -= >>= <<= &= ^= |=

assignment

Right-to-left

17

,

comma

Left-to-right

 

Sample program that shows the meaning of precedence:

                #include (iostream>

                using namespace std;

               

                int main ()

                {

                                int a=10 ,b=20, c=30, d, e, f;

                                d=a+a*b-c;

                                e=(a*b+a)/c;

                                f=(a*(b/c));

                                cout << d << endl;

                                cout << e << endl;

                                cout << f << endl;

                                return (0);

                }

 

The output of the program is:

 

180

7

0

 

In the given program:

The statement a+a*b-c; a*b is evaluated first then the operators +and – which gives the final result of 180.

In the statement (a*b+a)/c, the operators inside the parenthesis is first evaluated. The multiplication operator is evaluated before the addition operator. Then the last operator is the division which gives the final result of 7.

In the last statement parentheses are also used, the innermost expression is evaluated first giving the result of 0 then multiplied with the last variable which gives the final result of 0.

Answered By 0 points N/A #124168

C++ operators and their precedence level

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Hi Eleanor,

C++ uses operators to operate and manage its variables and constants.

You may see that C++, unlike any other languages which uses words, uses signs which are not part of the alphabet but are accessible in the keyboard. This is what makes C++ code international and shorter.

There are 55 operators all in all on C++. This includes arithmetic, comparison/relational, logical, bitwise, compound assignment, member and pointer and other operators.

To see the precedence of the operators, you can check here:

 

Sample expression b = c < f ? c++ : c = f will be parsed in C++ as b = (c < f ? c++ : (c = f))
 
Aristono.

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